More about connections: a toy example

In this post we are going to work out the concepts of the previous entry to develop the intuition of the ideas.

Let's take \(M=\mathbb{R}\) and \(E=M \times \mathbb{R}=\mathbb{R}\times \mathbb{R}\). Smooth sections of this bundle \(\pi: E\mapsto M\) can be identified with smooth functions
\[
f:\mathbb{R}\longmapsto \mathbb{R}
\]
if we take the frame given by the constant section \(e(x)=(x,1)\). That is, a section would be
\[
\sigma(x)=f(x) e(x)
\]
where \(f(x)\) is any smooth function.


Suppose we have a generic connection defined on \(E\), \(\nabla\). We have
\[
\nabla(\sigma)=e\otimes df+e\otimes f(x) \omega(x)
\]
being \(\omega\) a 1-form, the connection form. With this set up, the usual derivative correspond to a connection whose connection form is \(\omega=0\). In effect, for the vector field \(\partial x\) on \(M\) we have
\[
\nabla(\sigma)(\partial x)=df(\partial x) e+0=f'(x) e
\]



But now, let's take a different \(\omega\) to obtain a new notion of derivative. For example, we can choose \(\omega(x)=2dx\). In this case, when we derive the section \(\sigma\) we obtain
\[
\nabla(\sigma)(\partial x)=df(\partial x) e+f(x)2dx(\partial x)e=(f'(x)+2f(x))e
\]

So this new notion of derivative associates
\[
f(x)\longmapsto f'(x)+2f(x)
\]

What functions would correspond to constant functions? Well, those whose derivative were 0, that is
\[
f'(x)+2f(x)=0
\]

Solving this ODE we obtain the family
\[
f(x)=Ke^{-2x}
\]
that corresponds to constant functions.


Let's stop. What's going on here? When we learn to derive usual functions
\[
f:\mathbb{R}\longrightarrow \mathbb{R}
\]
we assume that the arriving \(\mathbb{R}\) is always the same. But in a more general sense, we can think that every \(f(x)\) lives in a different space \(E_x=\mathbb{R}\), or the same space but measured with different units. For example, imagine that we live in a 1 dimensional world, and want to study the movement of a particle that is initially at 1 meter from us. To do this, we check the distance every 1 second and annotate it in a table. We say that the particle is not moving if its distance is always 1.


But now, imagine that the stick we use to measure the distance is increasing its size (maybe because of rising temperatures, who knows). For example, suppose that the size of the stick is \(e^{2t}\), where \(t\) is time. Then a distance \(d\) measured at time 0 would correspond to a distance \(d e^{-2t}\) measured at time \(t\) (think about it). Therefore, we would consider that the particle is at rest (constant position function) when its curve is of the form
\[
f(t)=de^{-2t}
\]





These lines are interpreted as joining point in \(\mathbb{R}\) that can be identified as the same. They act like parallel transporters. Their tangent lines define the horizontal subbundle of \(TE\).

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