Transformations of observables generated by an observable

In Classical Mechanics, any function \(f \in \mathcal{C}^{\infty}(T^*Q)\) is called an observable. They constitute a commutative algebra that is, in fact, a Poisson algebra due to the existence of the Poisson bracket \(\{-,-\}\). If you fix any \(f\in \mathcal{C}^{\infty}(T^*Q)\) then you get a 1-parameter local tranformation group for \( \mathcal{C}^{\infty}(T^*Q)\) in the following way.

First, you have the vector field \(X_f\) given by
\[
X_f=\{-,f\}
\]

Then, the fundamental theorem of ODEs let you assure that there exists the local flow
\[
\phi_s:T^*Q \mapsto T^*Q
\]
such that
  1. \(\phi_0=id\)
  2. \(\frac{d}{ds} \phi_s (m)|_{s=0}=X_f \)
  3. \(\phi_s \circ \phi_t=\phi_{s+t}\)

Now, we can define a family of transformations of observables
\[
F^{\phi_s}: \mathcal{C}^{\infty}(T^*Q) \longmapsto \mathcal{C}^{\infty}(T^*Q)
\]
by means of
\[
g \longmapsto F^{\phi_s}(g)=g \circ \phi_s
\]


I interpret observables as little machines that you can place where you want (in a broad sense of the meaning of "where", because this includes time and any other variable properties like temperature or energy, but we are treating them as "space") and then you can read a number in their screen. What this is telling to us is that given any of those machines, say \(f\), we can construct a modifier of machines that depends on one parameter and that yields a group. Observe that the definition of the modifier use the symplectic form, or the Poisson bracket, which is a bit annoying for me. I think that this would be removed if we go to the \(C^*-\)algebra formulation...


On the other hand, we have that

\[
\frac{d}{ds} F^{\phi_s}(g)=\frac{d}{ds}(g\circ \phi_s)=dg_{\phi_{s}(-)} \cdot X_f=X_f(g\circ \phi_s)=\{F^{\phi_s}(g),f\}
\]
and
\[
F^{\phi_0}(g)=g.
\]

And also, \(F^{\phi_s}\) respect the Poisson algebra structure.



Reciprocally, if we start with a function \(f\) and an associated family of transformations of \(\mathcal{C}^{\infty}(T^*Q)\) to \(\mathcal{C}^{\infty}(T^*Q)\) that preserve the structure of Poisson algebra and such that
  • \(\frac{d}{d t} F_{t}^{f}(g)=\left\{F_{t}^{f}(g),f \right\}\)
  • \(F_{0}^{f}(g)=g\)

we can define a flow \(\phi_t\) in \(T^*Q\) such that
\[
F_t^f(g)=F^{\phi_t}(g)
\]

We proceed by taking the vector field \(\{-,f\}\) and the associated flow \(\phi_t\), and using the two required properties. Since
\[
\frac{d}{ds} F^{\phi_s}(g)=\frac{d}{d s} F_{s}^{f}(g)
\]
and
\[
F^{\phi_0}(g)=F_{0}^{f}(g)
\]
we can show that \(F_s^f(g)=F^{\phi_s}(g)\) by fixing a point \(P\in T^*Q\).


We indeed have a duality, between transformations in \(T^* Q\) and transformation in \(\mathcal{C}^{\infty}(T^* Q)\). Why do we pass from the flow in the phase space \(T^*Q\) to the flow of observables? Because this way, I guess, we can formulate everything in terms of algebras, and we get a deeper insight in the connection with QM.

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